Introduction for functions in math:
A math function is a one of the type of relation. In a function, number 2 ordered pairs can have the same first element and a different second element. That is, for a functions, corresponding to every 1st element of the ordered pairs, there must be a different 2nd element. i.e. In a function we can't have ordered pairs of the form (a1, b1) and (a2, b2) with a1 = a2 and b1 ? b2. It is called as function. Types of functions and example problems are given below.
Understanding Conic Equations is always challenging for me but thanks to all math help websites to help me out.
Types of functions in math:
Let us see about some important math functions types are given below.
1. Into function:
A function f: A ? B is said to be into function if its range is a proper subset of its co-domain.
Let f: A ? B, where A = {a, b, c}, B = {p, q, r, s} be defined by f(a) = p, f(b) = q, f(c) = r. Then the range of f is {p, q, r}, a proper subset of B `=>` f is an into function.
Let g: C ? D where C = {6, 1, 3, 4} and D = {m, n, p} be defined by g(6) = p, g(1) = p, g(3) = p and g(4) = p. Then g is into as its range {p} is a proper subset of D `=>` g is an into function.
2. Onto function:
A function from A to B is said to be an onto function if its range is equal to its co-domain B. In other words, f is called ‘onto’ if every element of B has a Preimage in A.
For example:
(i) Let A = {1, 3, 4, 5} and B = {3, 6,7}, f(1) = 6, f(3) = 3, f(4) = 7 and f(5) = 6. Evidently the range of f is B and is onto.
(ii) Consider g : C ? D where C = {3, –3, 4, –4} and D = {9, 16} and g(3) = 9, g(–3) = 9, g(4) = 16, g(–4) = 16. Evidently g is onto.
3. One to one function:
A function f from A to B is called an one to one function (one – one function) if for a, b ? A, where a ? b, we must have f(a) ? f(b). Here the domain and the range of f will have the same cardinality.
For example:
(i) Let f : A ? B where A = {a, b, c}, B = {–1, 2, 3, 5} f(a) = 5, f(b) = –1, f(c) = 3. Then f is one to one. Note that the range of f is a subset of B and so f is into. We call such functions as one to one into.
(ii) Let g: C ? D where C = {3, 5, 7} and D = {4, 6, 8} be defined by g(3) = 4, g(5) = 6, g(7) = 8. Then g is one to one and the range of g is equal to the co domain D. So g is onto. We call such functions as one to one onto.
4. Constant function:
A function f from A to B is called a constant function if every element of A has the same image in B.
Let A = {4, 5, 6, 7}, B = {7, 8, 10} and if f : A ? B is defined by f(4) = 10, f(5) = 10, f(6) = 10 and f(7) = 10 then f is constant function. I have recently faced lot of problem while learning algebra 2 math help, But thank to online resources of math which helped me to learn myself easily on net.
Example problem for functions in math:
Example problem:
Given A = {a, b, c, d}, B = {p, q, r, s} and if f : A ? B is defined as below find the type of the function:
(i) f = {(a, p), (b, p), (c, q), (d, r)}
(ii) f = {(a, q), (b, q), (c, q), (d, q)}
(iii) f = {(a, p), (b, q), (c, r), (d, s)}
Solution:
(i) Since a, b are mapped to p ? B and the element s of B has no Preimage in A, it is many to one and into function
(ii) All the elements of A are mapped to the similar element q ? B. Hence it is a constant function. It is also many to one.
(iii) Because all the images are different and no element in B is left out without any Preimage, f represents a one to one and onto function.
A math function is a one of the type of relation. In a function, number 2 ordered pairs can have the same first element and a different second element. That is, for a functions, corresponding to every 1st element of the ordered pairs, there must be a different 2nd element. i.e. In a function we can't have ordered pairs of the form (a1, b1) and (a2, b2) with a1 = a2 and b1 ? b2. It is called as function. Types of functions and example problems are given below.
Understanding Conic Equations is always challenging for me but thanks to all math help websites to help me out.
Types of functions in math:
Let us see about some important math functions types are given below.
1. Into function:
A function f: A ? B is said to be into function if its range is a proper subset of its co-domain.
Let f: A ? B, where A = {a, b, c}, B = {p, q, r, s} be defined by f(a) = p, f(b) = q, f(c) = r. Then the range of f is {p, q, r}, a proper subset of B `=>` f is an into function.
Let g: C ? D where C = {6, 1, 3, 4} and D = {m, n, p} be defined by g(6) = p, g(1) = p, g(3) = p and g(4) = p. Then g is into as its range {p} is a proper subset of D `=>` g is an into function.
2. Onto function:
A function from A to B is said to be an onto function if its range is equal to its co-domain B. In other words, f is called ‘onto’ if every element of B has a Preimage in A.
For example:
(i) Let A = {1, 3, 4, 5} and B = {3, 6,7}, f(1) = 6, f(3) = 3, f(4) = 7 and f(5) = 6. Evidently the range of f is B and is onto.
(ii) Consider g : C ? D where C = {3, –3, 4, –4} and D = {9, 16} and g(3) = 9, g(–3) = 9, g(4) = 16, g(–4) = 16. Evidently g is onto.
3. One to one function:
A function f from A to B is called an one to one function (one – one function) if for a, b ? A, where a ? b, we must have f(a) ? f(b). Here the domain and the range of f will have the same cardinality.
For example:
(i) Let f : A ? B where A = {a, b, c}, B = {–1, 2, 3, 5} f(a) = 5, f(b) = –1, f(c) = 3. Then f is one to one. Note that the range of f is a subset of B and so f is into. We call such functions as one to one into.
(ii) Let g: C ? D where C = {3, 5, 7} and D = {4, 6, 8} be defined by g(3) = 4, g(5) = 6, g(7) = 8. Then g is one to one and the range of g is equal to the co domain D. So g is onto. We call such functions as one to one onto.
4. Constant function:
A function f from A to B is called a constant function if every element of A has the same image in B.
Let A = {4, 5, 6, 7}, B = {7, 8, 10} and if f : A ? B is defined by f(4) = 10, f(5) = 10, f(6) = 10 and f(7) = 10 then f is constant function. I have recently faced lot of problem while learning algebra 2 math help, But thank to online resources of math which helped me to learn myself easily on net.
Example problem for functions in math:
Example problem:
Given A = {a, b, c, d}, B = {p, q, r, s} and if f : A ? B is defined as below find the type of the function:
(i) f = {(a, p), (b, p), (c, q), (d, r)}
(ii) f = {(a, q), (b, q), (c, q), (d, q)}
(iii) f = {(a, p), (b, q), (c, r), (d, s)}
Solution:
(i) Since a, b are mapped to p ? B and the element s of B has no Preimage in A, it is many to one and into function
(ii) All the elements of A are mapped to the similar element q ? B. Hence it is a constant function. It is also many to one.
(iii) Because all the images are different and no element in B is left out without any Preimage, f represents a one to one and onto function.
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