Word Math Problems

Introduction to Word sums math problem

The Word sums math problem are can be expressed in algebraic or equation format. The word problems can be specified in simple form. Here also algebra concept is helped to do the word sum math problems. Algebra is an important part in mathematics which is used to find unknown variables by using the known variable. Let we see about the words sum math problems. Having problem with free algebra 2 answers keep reading my upcoming posts, i will try to help you.


Solved Examples in word sums math problem


Example 1 in word sums math problem
A Boy crosses an 800 m long street in 4 minutes. What is his speed in km per hour?

Solution: First we  have convert the algebra word problem to a numerical form to get the solution.

800

Speed = _____ * 60

4

m/sec = 5 m/sec

Now convert the m/sec to km/hr

= ( 5 * 120/4 )

= 150 km/hr

Example 2 in word sum math problem :
Maria has 12 cars and 16 Venus. How many cars does she have?

Solution:

Let P = Total number of cars
The sum of 12 cars and 16 Venus is equal to the total number of cars . It translates the problem into an equation.
P = 12 + 16

Solve this equation.
Let P = Total number of cars

P = 28.

There are 28 total numbers of cars

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Some more Solved Examples in word sums math problem


Example 3 in word sums math problem
There were 88 apples in each enclosure. 44 such enclosure of apples were serviced to a company. 14 apples were decayed and had to be thrown away. The remaining apples were packed into boxes of 4 apples each. How many boxes of apples were there?

Sol:

Find the total number of apples serviced to a company.

44 × 88 = 3872

The total number of apples delivered to company was 3872.

Get the number of remaining apples.

3872 – 14 = 3858

Get the number of boxes of apples.

3858 ÷ 4 = 964.5

There were 964.5 boxes of apples

Example 4 in word sums math problem
The normal of a list of 10 numbers is 30. If we throw out one of the numbers, the normal of the remaining numbers is 15. What is the number that was removed?

Sol:

Step 1: The throw out the number could be obtained by difference between the sum of original 8 numbers and the sum of remaining 15 numbers i.e.

Sum of original 10 numbers – sum of remaining 15 numbers

Step 2: Using the formula

Sum of terms = Average* Number of terms

Sum of original 10 numbers = 30 × 10 = 300

Sum of remaining 15 numbers = 15 × 10 = 150

Step 3: Using the formula from step 1

Number removed = sum of original 10 numbers – sum of remaining 15 numbers

500 – 150 = 350

Answer: The number removed is 350.

Technical Math Problems

Introduction to technical math problems:

Mathematics is basically the study about quantity, structure, space, change, etc... It is the systematic study of the shapes and motions of physical objects. Mathematics is applied widely in all areas. Mathematics has been used throught the world which is a basic and essential tool for all fields .In this article we shall discuss about technical math problems. Understanding Do Math Problems is always challenging for me but thanks to all math help websites to help me out.


Technical math Problems:


The problems which are derived  from mathematical techniques are known as technical math problems. There are various techniques related with mathematics .Let us see some math problems which are solved technically by various techniques.


Technical Problem 1:


A clock is started at noon. By 20 minutes past 5, the hour hand has turned

Through________ degrees

Explanation:

Angle traced by hour hand in 12 hrs = 360 degrees

Angle traced by hour hand in 5 hrs 20 min ie)  16/3hrs=((360/12)*(16/3))

=160 degrees

Technical  Problem2:

If a quarter kg of potato costs $1200 , how many paise will 200 gm cost?

Explanation:

Let the required weight be X kg.

hence   250 : 200 :: 80 :  X      250 *X= 200*160

X=200*160/250

X= $96

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Technical Problem 3:


Mike started a business investing the amount about seven thousand rupees. Lincoln joined him after six   months with  an amount of  $10500and Sami joined them with fourteen thousand after another  six months. The profit should be shared in what ratio for Mike, Lincoln and  Sami respectively, 3 years after Mike started the business?

Explanation:

Mike : Lincoln: Sami = (36 x 7000) : (10500 x 30) : (14000 x 24) = 12 : 15 : 16.

Technical  Problem 4:

Adam can do a certain work in the same time in which Bollinger and Clarke together can do it. If Adam and Bolllinger together could do it in 10 days and Clarke alone in 30 days, then Adam.Bollinger and clarke combined together and they could do it in ____days:

Explanation:

Let us take Adam as A,Bollinger as B and Clarke as C

(A + B)'s 1 day's work=1/10

C's 1 day's work=1/30

(A + B + C)'s 1 day's work =((1/10)+(1/30))=4/30……(1)

A's 1 day's work = (B + C)'s 1 day's work ………….... (2)

From (1) and (2), we get: 2 x (A's 1 day's work)

So, Adam.Bollinger and clarke combined together and they could do it  in 7and half a days.